Gay Lussac’s Law

Definition: Gay Lussac’s Law describes the relationship between temperature (T) and Pressure (P) while number of moles (n) and volume (V) remain constant.

Relation: T and P are directly proportional so as temperature increases, pressure increases.

T α P

Equation:

GayLussacEquation

Example:

GLExample

Imagine you’ve just picked up a bunch of balloons for a party and you leave them in the car while running errands on a hot day. Since the balloons are sealed, the volume (V↔) is held constant so while the temperature inside the car increases (↑T) and gas naturally wants to expand (Boyle’s Law), it cannot. So the pressure inside the balloon increases (P↑) until it becomes too much and balloons pop. Looks like you have one more errands to re-run. True story!

Problem: A sample of CO2 gas at 10°C has a pressure of 1.2 atm. What is the pressure when the temperature is increased to 25°C?

GIVEN:

T1 = 10° → K Conversion Required → 10°C + 273 = 283K
P= 1.2 atm
P= ?
T= 25° → K Conversion Required → 25°C + 273 = 298K

GLEquation

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